The length of rod E is
34 of the length of rod H and the length of rod H is
23 of the length of rod F and
210 of the length of rod G. What fraction of the total length of the 4 rods is rod F?
E |
H |
F |
G |
Total |
3x1 |
4x1 |
|
|
|
|
2x2 |
3x2 |
|
|
|
2x2 |
|
10x2 |
|
3 u |
4 u |
6 u |
20 u |
33 u |
The length of rod H is repeated. Make the length of rod H the same. LCM of 4 and 2 is 4.
Total length of all the 4 rods
= 3 u + 4 u + 6 u + 20 u
= 33 u
Rod FTotal Length =
633 =
211Answer(s):
211