The length of metallic rod A is
23 of the length of metallic rod D and the length of metallic rod D is
13 of the length of metallic rod B and
18 of the length of metallic rod C. What fraction of the total length of the 4 metallic rods is metallic rod C?
A |
D |
B |
C |
Total |
2x1 |
3x1 |
|
|
|
|
1x3 |
3x3 |
|
|
|
1x3 |
|
8x3 |
|
2 u |
3 u |
9 u |
24 u |
38 u |
The length of metallic rod D is repeated. Make the length of metallic rod D the same. LCM of 3 and 1 is 3.
Total length of all the 4 metallic rods
= 2 u + 3 u + 9 u + 24 u
= 38 u
Metallic Rod CTotal Length =
2438 =
1219Answer(s):
1219