The length of metallic rod L is
34 of the length of metallic rod P and the length of metallic rod P is
15 of the length of metallic rod M and
16 of the length of metallic rod N. What fraction of the total length of the 4 metallic rods is metallic rod N?
L |
P |
M |
N |
Total |
3x1 |
4x1 |
|
|
|
|
1x4 |
5x4 |
|
|
|
1x4 |
|
6x4 |
|
3 u |
4 u |
20 u |
24 u |
51 u |
The length of metallic rod P is repeated. Make the length of metallic rod P the same. LCM of 4 and 1 is 4.
Total length of all the 4 metallic rods
= 3 u + 4 u + 20 u + 24 u
= 51 u
Metallic Rod NTotal Length =
2451 =
817Answer(s):
817