The length of rod D is
34 of the length of rod G and the length of rod G is
12 of the length of rod E and
15 of the length of rod F. What fraction of the total length of the 4 rods is rod F?
D |
G |
E |
F |
Total |
3x1 |
4x1 |
|
|
|
|
1x4 |
2x4 |
|
|
|
1x4 |
|
5x4 |
|
3 u |
4 u |
8 u |
20 u |
35 u |
The length of rod G is repeated. Make the length of rod G the same. LCM of 4 and 1 is 4.
Total length of all the 4 rods
= 3 u + 4 u + 8 u + 20 u
= 35 u
Rod FTotal Length =
2035 =
47Answer(s):
47