The length of rod E is
12 of the length of rod H and the length of rod H is
35 of the length of rod F and
38 of the length of rod G. What fraction of the total length of the 4 rods is rod F?
E |
H |
F |
G |
Total |
1x3 |
2x3 |
|
|
|
|
3x2 |
5x2 |
|
|
|
3x2 |
|
8x2 |
|
3 u |
6 u |
10 u |
16 u |
35 u |
The length of rod H is repeated. Make the length of rod H the same. LCM of 2 and 3 is 6.
Total length of all the 4 rods
= 3 u + 6 u + 10 u + 16 u
= 35 u
Rod FTotal Length =
1035 =
27Answer(s):
27