The length of rod E is
23 of the length of rod H and the length of rod H is
15 of the length of rod F and
18 of the length of rod G. What fraction of the total length of the 4 rods is rod G?
E |
H |
F |
G |
Total |
2x1 |
3x1 |
|
|
|
|
1x3 |
5x3 |
|
|
|
1x3 |
|
8x3 |
|
2 u |
3 u |
15 u |
24 u |
44 u |
The length of rod H is repeated. Make the length of rod H the same. LCM of 3 and 1 is 3.
Total length of all the 4 rods
= 2 u + 3 u + 15 u + 24 u
= 44 u
Rod GTotal Length =
2444 =
611Answer(s):
611