The length of metallic rod E is
34 of the length of metallic rod H and the length of metallic rod H is
15 of the length of metallic rod F and
13 of the length of metallic rod G. What fraction of the total length of the 4 metallic rods is metallic rod G?
E |
H |
F |
G |
Total |
3x1 |
4x1 |
|
|
|
|
1x4 |
5x4 |
|
|
|
1x4 |
|
3x4 |
|
3 u |
4 u |
20 u |
12 u |
39 u |
The length of metallic rod H is repeated. Make the length of metallic rod H the same. LCM of 4 and 1 is 4.
Total length of all the 4 metallic rods
= 3 u + 4 u + 20 u + 12 u
= 39 u
Metallic Rod GTotal Length =
1239 =
413Answer(s):
413