The length of rod B is
23 of the length of rod E and the length of rod E is
15 of the length of rod C and
15 of the length of rod D. What fraction of the total length of the 4 rods is rod C?
B |
E |
C |
D |
Total |
2x1 |
3x1 |
|
|
|
|
1x3 |
5x3 |
|
|
|
1x3 |
|
5x3 |
|
2 u |
3 u |
15 u |
15 u |
35 u |
The length of rod E is repeated. Make the length of rod E the same. LCM of 3 and 1 is 3.
Total length of all the 4 rods
= 2 u + 3 u + 15 u + 15 u
= 35 u
Rod CTotal Length =
1535 =
37Answer(s):
37