The length of metallic rod E is
12 of the length of metallic rod H and the length of metallic rod H is
13 of the length of metallic rod F and
19 of the length of metallic rod G. What fraction of the total length of the 4 metallic rods is metallic rod G?
E |
H |
F |
G |
Total |
1x1 |
2x1 |
|
|
|
|
1x2 |
3x2 |
|
|
|
1x2 |
|
9x2 |
|
1 u |
2 u |
6 u |
18 u |
27 u |
The length of metallic rod H is repeated. Make the length of metallic rod H the same. LCM of 2 and 1 is 2.
Total length of all the 4 metallic rods
= 1 u + 2 u + 6 u + 18 u
= 27 u
Metallic Rod GTotal Length =
1827 =
23Answer(s):
23