The length of metallic rod V is
45 of the length of metallic rod Y and the length of metallic rod Y is
35 of the length of metallic rod W and
38 of the length of metallic rod X. What fraction of the total length of the 4 metallic rods is metallic rod X?
V |
Y |
W |
X |
Total |
4x3 |
5x3 |
|
|
|
|
3x5 |
5x5 |
|
|
|
3x5 |
|
8x5 |
|
12 u |
15 u |
25 u |
40 u |
92 u |
The length of metallic rod Y is repeated. Make the length of metallic rod Y the same. LCM of 5 and 3 is 15.
Total length of all the 4 metallic rods
= 12 u + 15 u + 25 u + 40 u
= 92 u
Metallic Rod XTotal Length =
4092 =
1023Answer(s):
1023