The length of rod D is
23 of the length of rod G and the length of rod G is
25 of the length of rod E and
210 of the length of rod F. What fraction of the total length of the 4 rods is rod E?
D |
G |
E |
F |
Total |
2x2 |
3x2 |
|
|
|
|
2x3 |
5x3 |
|
|
|
2x3 |
|
10x3 |
|
4 u |
6 u |
15 u |
30 u |
55 u |
The length of rod G is repeated. Make the length of rod G the same. LCM of 3 and 2 is 6.
Total length of all the 4 rods
= 4 u + 6 u + 15 u + 30 u
= 55 u
Rod ETotal Length =
1555 =
311Answer(s):
311