The length of metallic rod B is
34 of the length of metallic rod E and the length of metallic rod E is
25 of the length of metallic rod C and
24 of the length of metallic rod D. What fraction of the total length of the 4 metallic rods is metallic rod C?
B |
E |
C |
D |
Total |
3x1 |
4x1 |
|
|
|
|
2x2 |
5x2 |
|
|
|
2x2 |
|
4x2 |
|
3 u |
4 u |
10 u |
8 u |
25 u |
The length of metallic rod E is repeated. Make the length of metallic rod E the same. LCM of 4 and 2 is 4.
Total length of all the 4 metallic rods
= 3 u + 4 u + 10 u + 8 u
= 25 u
Metallic Rod CTotal Length =
1025 =
25Answer(s):
25