The length of metallic rod B is
45 of the length of metallic rod E and the length of metallic rod E is
15 of the length of metallic rod C and
14 of the length of metallic rod D. What fraction of the total length of the 4 metallic rods is metallic rod D?
B |
E |
C |
D |
Total |
4x1 |
5x1 |
|
|
|
|
1x5 |
5x5 |
|
|
|
1x5 |
|
4x5 |
|
4 u |
5 u |
25 u |
20 u |
54 u |
The length of metallic rod E is repeated. Make the length of metallic rod E the same. LCM of 5 and 1 is 5.
Total length of all the 4 metallic rods
= 4 u + 5 u + 25 u + 20 u
= 54 u
Metallic Rod DTotal Length =
2054 =
1027Answer(s):
1027