The length of metallic rod G is
45 of the length of metallic rod K and the length of metallic rod K is
35 of the length of metallic rod H and
32 of the length of metallic rod J. What fraction of the total length of the 4 metallic rods is metallic rod J?
G |
K |
H |
J |
Total |
4x3 |
5x3 |
|
|
|
|
3x5 |
5x5 |
|
|
|
3x5 |
|
2x5 |
|
12 u |
15 u |
25 u |
10 u |
62 u |
The length of metallic rod K is repeated. Make the length of metallic rod K the same. LCM of 5 and 3 is 15.
Total length of all the 4 metallic rods
= 12 u + 15 u + 25 u + 10 u
= 62 u
Metallic Rod JTotal Length =
1062 =
531Answer(s):
531