The length of metallic rod E is
23 of the length of metallic rod H and the length of metallic rod H is
13 of the length of metallic rod F and
17 of the length of metallic rod G. What fraction of the total length of the 4 metallic rods is metallic rod G?
E |
H |
F |
G |
Total |
2x1 |
3x1 |
|
|
|
|
1x3 |
3x3 |
|
|
|
1x3 |
|
7x3 |
|
2 u |
3 u |
9 u |
21 u |
35 u |
The length of metallic rod H is repeated. Make the length of metallic rod H the same. LCM of 3 and 1 is 3.
Total length of all the 4 metallic rods
= 2 u + 3 u + 9 u + 21 u
= 35 u
Metallic Rod GTotal Length =
2135 =
35Answer(s):
35