The length of metallic rod M is
34 of the length of metallic rod Q and the length of metallic rod Q is
13 of the length of metallic rod N and
18 of the length of metallic rod P. What fraction of the total length of the 4 metallic rods is metallic rod N?
M |
Q |
N |
P |
Total |
3x1 |
4x1 |
|
|
|
|
1x4 |
3x4 |
|
|
|
1x4 |
|
8x4 |
|
3 u |
4 u |
12 u |
32 u |
51 u |
The length of metallic rod Q is repeated. Make the length of metallic rod Q the same. LCM of 4 and 1 is 4.
Total length of all the 4 metallic rods
= 3 u + 4 u + 12 u + 32 u
= 51 u
Metallic Rod NTotal Length =
1251 =
417Answer(s):
417