The length of rod A is
45 of the length of rod D and the length of rod D is
14 of the length of rod B and
17 of the length of rod C. What fraction of the total length of the 4 rods is rod B?
A |
D |
B |
C |
Total |
4x1 |
5x1 |
|
|
|
|
1x5 |
4x5 |
|
|
|
1x5 |
|
7x5 |
|
4 u |
5 u |
20 u |
35 u |
64 u |
The length of rod D is repeated. Make the length of rod D the same. LCM of 5 and 1 is 5.
Total length of all the 4 rods
= 4 u + 5 u + 20 u + 35 u
= 64 u
Rod BTotal Length =
2064 =
516Answer(s):
516