The length of metallic rod U is
45 of the length of metallic rod X and the length of metallic rod X is
13 of the length of metallic rod V and
13 of the length of metallic rod W. What fraction of the total length of the 4 metallic rods is metallic rod W?
U |
X |
V |
W |
Total |
4x1 |
5x1 |
|
|
|
|
1x5 |
3x5 |
|
|
|
1x5 |
|
3x5 |
|
4 u |
5 u |
15 u |
15 u |
39 u |
The length of metallic rod X is repeated. Make the length of metallic rod X the same. LCM of 5 and 1 is 5.
Total length of all the 4 metallic rods
= 4 u + 5 u + 15 u + 15 u
= 39 u
Metallic Rod WTotal Length =
1539 =
513Answer(s):
513