The length of metallic rod A is
23 of the length of metallic rod D and the length of metallic rod D is
12 of the length of metallic rod B and
15 of the length of metallic rod C. What fraction of the total length of the 4 metallic rods is metallic rod B?
A |
D |
B |
C |
Total |
2x1 |
3x1 |
|
|
|
|
1x3 |
2x3 |
|
|
|
1x3 |
|
5x3 |
|
2 u |
3 u |
6 u |
15 u |
26 u |
The length of metallic rod D is repeated. Make the length of metallic rod D the same. LCM of 3 and 1 is 3.
Total length of all the 4 metallic rods
= 2 u + 3 u + 6 u + 15 u
= 26 u
Metallic Rod BTotal Length =
626 =
313Answer(s):
313