Luis, Bryan, Julian and Ken shared $108. Ken received
45 of the total amount of money received by Luis, Bryan and Julian. Luis received
13 of the total amount for Bryan and Julian. Bryan received
23 as much money as Julian. If Bryan gave all his money to Ken, how much did Ken have more than Luis in the end?
Luis |
Bryan |
Julian |
Ken |
Total |
5x4 |
4x4 |
9x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
16 u |
36 u |
The total amount that Bryan and Julian have is repeated. Make the total amount of Bryan and Julian the same. LCM of 5 and 3 is 15.
The total amount that Luis, Bryan and Julian have is repeated. Make the total amount of Luis, Bryan and Julian the same. LCM of 20 and 5 is 20.
Total amount that Luis, Bryan, Julian and Ken shared = 36 u
36 u = 108
1 u = 108 ÷ 36 = 3
|
Luis |
Bryan |
Julian |
Ken |
Before |
5 u |
6 u |
9 u |
16 u |
Change |
|
- 6 u |
|
+ 6 u |
After |
5 u |
0 u |
9 u |
22 u |
Amount that Ken had if Bryan gave him all his money
= 16 u + 6 u
= 22 u
Amount that Ken had more than Luis
= 22 u - 5 u
= 17 u
= 17 x 3
= $51
Answer(s): $51