Mark, Fred, Howard and Gabriel shared $560. Gabriel received
34 of the total amount of money received by Mark, Fred and Howard. Mark received
23 of the total amount for Fred and Howard. Fred received
13 as much money as Howard. If Howard gave all his money to Gabriel, how much did Gabriel have more than Fred in the end?
Mark |
Fred |
Howard |
Gabriel |
Total |
4x5 |
3x5 |
7x5 |
2x4 |
3x4 |
|
|
|
1x3 |
3x3 |
|
|
8 u |
3 u |
9 u |
15 u |
35 u |
The total amount that Fred and Howard have is repeated. Make the total amount of Fred and Howard the same. LCM of 4 and 3 is 12.
The total amount that Mark, Fred and Howard have is repeated. Make the total amount of Mark, Fred and Howard the same. LCM of 20 and 4 is 20.
Total amount that Mark, Fred, Howard and Gabriel shared = 35 u
35 u = 560
1 u = 560 ÷ 35 = 16
|
Mark |
Fred |
Howard |
Gabriel |
Before |
8 u |
3 u |
9 u |
15 u |
Change |
|
|
- 9 u |
+ 9 u |
After |
8 u |
3 u |
0 u |
24 u |
Amount that Gabriel had if Howard gave him all his money
= 15 u + 9 u
= 24 u
Amount that Gabriel had more than Fred
= 24 u - 3 u
= 21 u
= 21 x 16
= $336
Answer(s): $336