David, Eric, Albert and Bryan shared $252. Bryan received
45 of the total amount of money received by David, Eric and Albert. David received
13 of the total amount for Eric and Albert. Eric received
23 as much money as Albert. If Albert gave all his money to Bryan, how much did Bryan have more than Eric in the end?
David |
Eric |
Albert |
Bryan |
Total |
5x4 |
4x4 |
9x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
16 u |
36 u |
The total amount that Eric and Albert have is repeated. Make the total amount of Eric and Albert the same. LCM of 5 and 3 is 15.
The total amount that David, Eric and Albert have is repeated. Make the total amount of David, Eric and Albert the same. LCM of 20 and 5 is 20.
Total amount that David, Eric, Albert and Bryan shared = 36 u
36 u = 252
1 u = 252 ÷ 36 = 7
|
David |
Eric |
Albert |
Bryan |
Before |
5 u |
6 u |
9 u |
16 u |
Change |
|
|
- 9 u |
+ 9 u |
After |
5 u |
6 u |
0 u |
25 u |
Amount that Bryan had if Albert gave him all his money
= 16 u + 9 u
= 25 u
Amount that Bryan had more than Eric
= 25 u - 6 u
= 19 u
= 19 x 7
= $133
Answer(s): $133