Jeremy, Sean, Dylan and Jenson shared $544. Jenson received ³₅ of the total amount of money received by Jeremy, Sean and Dylan. Jeremy received ¹₃ of the total amount for Sean and Dylan. Sean received ²₃ as much money as Dylan. If Dylan gave all his money to Jenson, how much did Jenson have more than Sean in the end?

Jeremy	Sean	Dylan	Jenson	Total
5x4			3x4	8x4
1x5	3x5
	2x3	3x3
5 u	6 u	9 u	12 u	32 u

The total amount that Sean and Dylan have is repeated.  Make the total amount of Sean and Dylan the same.  LCM of 5 and 3 is 15.

The total amount that Jeremy, Sean and Dylan have is repeated.  Make the total amount of Jeremy, Sean and Dylan the same. LCM of 20 and 5 is 20.

Total amount that Jeremy, Sean, Dylan and Jenson shared = 32 u

32 u = 544

1 u = 544 ÷ 32 = 17

	Jeremy	Sean	Dylan	Jenson
Before	5 u	6 u	9 u	12 u
Change			- 9 u	+ 9 u
After	5 u	6 u	0 u	21 u

Amount that Jenson had if Dylan gave him all his money
= 12 u + 9 u
= 21 u

Amount that Jenson had more than Sean
= 21 u - 6 u
= 15 u
= 15 x 17
= $255

Answer(s): $255