Brandon, Asher, Riordan and Carl shared $880. Carl received
56 of the total amount of money received by Brandon, Asher and Riordan. Brandon received
35 of the total amount for Asher and Riordan. Asher received
12 as much money as Riordan. If Asher gave all his money to Carl, how much did Carl have more than Brandon in the end?
Brandon |
Asher |
Riordan |
Carl |
Total |
6x4 |
5x4 |
11x4 |
3x3 |
5x3 |
|
|
|
1x5 |
2x5 |
|
|
9 u |
5 u |
10 u |
20 u |
44 u |
The total amount that Asher and Riordan have is repeated. Make the total amount of Asher and Riordan the same. LCM of 3 and 5 is 15.
The total amount that Brandon, Asher and Riordan have is repeated. Make the total amount of Brandon, Asher and Riordan the same. LCM of 24 and 6 is 24.
Total amount that Brandon, Asher, Riordan and Carl shared = 44 u
44 u = 880
1 u = 880 ÷ 44 = 20
|
Brandon |
Asher |
Riordan |
Carl |
Before |
9 u |
5 u |
10 u |
20 u |
Change |
|
- 5 u |
|
+ 5 u |
After |
9 u |
0 u |
10 u |
25 u |
Amount that Carl had if Asher gave him all his money
= 20 u + 5 u
= 25 u
Amount that Carl had more than Brandon
= 25 u - 9 u
= 16 u
= 16 x 20
= $320
Answer(s): $320