Elijah, Pierre, Tommy and Caden shared $576. Caden received
35 of the total amount of money received by Elijah, Pierre and Tommy. Elijah received
13 of the total amount for Pierre and Tommy. Pierre received
23 as much money as Tommy. If Pierre gave all his money to Caden, how much did Caden have more than Elijah in the end?
Elijah |
Pierre |
Tommy |
Caden |
Total |
5x4 |
3x4 |
8x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
12 u |
32 u |
The total amount that Pierre and Tommy have is repeated. Make the total amount of Pierre and Tommy the same. LCM of 5 and 3 is 15.
The total amount that Elijah, Pierre and Tommy have is repeated. Make the total amount of Elijah, Pierre and Tommy the same. LCM of 20 and 5 is 20.
Total amount that Elijah, Pierre, Tommy and Caden shared = 32 u
32 u = 576
1 u = 576 ÷ 32 = 18
|
Elijah |
Pierre |
Tommy |
Caden |
Before |
5 u |
6 u |
9 u |
12 u |
Change |
|
- 6 u |
|
+ 6 u |
After |
5 u |
0 u |
9 u |
18 u |
Amount that Caden had if Pierre gave him all his money
= 12 u + 6 u
= 18 u
Amount that Caden had more than Elijah
= 18 u - 5 u
= 13 u
= 13 x 18
= $234
Answer(s): $234