Gabriel, Sean, Luke and Jeremy shared $252. Jeremy received
16 of the total amount of money received by Gabriel, Sean and Luke. Gabriel received
45 of the total amount for Sean and Luke. Sean received
13 as much money as Luke. If Sean gave all his money to Jeremy, how much did Jeremy have more than Gabriel in the end?
Gabriel |
Sean |
Luke |
Jeremy |
Total |
6x6 |
1x6 |
7x6 |
4x4 |
5x4 |
|
|
|
1x5 |
3x5 |
|
|
16 u |
5 u |
15 u |
6 u |
42 u |
The total amount that Sean and Luke have is repeated. Make the total amount of Sean and Luke the same. LCM of 4 and 5 is 20.
The total amount that Gabriel, Sean and Luke have is repeated. Make the total amount of Gabriel, Sean and Luke the same. LCM of 36 and 6 is 36.
Total amount that Gabriel, Sean, Luke and Jeremy shared = 42 u
42 u = 252
1 u = 252 ÷ 42 = 6
|
Gabriel |
Sean |
Luke |
Jeremy |
Before |
16 u |
5 u |
15 u |
6 u |
Change |
|
- 5 u |
|
+ 5 u |
After |
16 u |
0 u |
15 u |
11 u |
Amount that Jeremy had if Sean gave him all his money
= 6 u + 5 u
= 11 u
Amount that Jeremy had more than Gabriel
= 11 u - 16 u
= -5 u
= -5 x 6
= $-30
Answer(s): $-30