Sam, Howard, Ken and Cody shared $1188. Cody received ⁵₆ of the total amount of money received by Sam, Howard and Ken. Sam received ⁴₅ of the total amount for Howard and Ken. Howard received ¹₃ as much money as Ken. If Ken gave all his money to Cody, how much did Cody have more than Howard in the end?

Sam	Howard	Ken	Cody	Total
6x6			5x6	11x6
4x4	5x4
	1x5	3x5
16 u	5 u	15 u	30 u	66 u

The total amount that Howard and Ken have is repeated.  Make the total amount of Howard and Ken the same.  LCM of 4 and 5 is 20.

The total amount that Sam, Howard and Ken have is repeated.  Make the total amount of Sam, Howard and Ken the same. LCM of 36 and 6 is 36.

Total amount that Sam, Howard, Ken and Cody shared = 66 u

66 u = 1188

1 u = 1188 ÷ 66 = 18

	Sam	Howard	Ken	Cody
Before	16 u	5 u	15 u	30 u
Change			- 15 u	+ 15 u
After	16 u	5 u	0 u	45 u

Amount that Cody had if Ken gave him all his money
= 30 u + 15 u
= 45 u

Amount that Cody had more than Howard
= 45 u - 5 u
= 40 u
= 40 x 18
= $720

Answer(s): $720