Dylan, Xavier, Simon and Oliver shared $90. Oliver received ¹₄ of the total amount of money received by Dylan, Xavier and Simon. Dylan received ³₅ of the total amount for Xavier and Simon. Xavier received ¹₂ as much money as Simon. If Xavier gave all his money to Oliver, how much did Oliver have more than Dylan in the end?

Dylan	Xavier	Simon	Oliver	Total
4x6			1x6	5x6
3x3	5x3
	1x5	2x5
9 u	5 u	10 u	6 u	30 u

The total amount that Xavier and Simon have is repeated.  Make the total amount of Xavier and Simon the same.  LCM of 3 and 5 is 15.

The total amount that Dylan, Xavier and Simon have is repeated.  Make the total amount of Dylan, Xavier and Simon the same. LCM of 24 and 4 is 24.

Total amount that Dylan, Xavier, Simon and Oliver shared = 30 u

30 u = 90

1 u = 90 ÷ 30 = 3

	Dylan	Xavier	Simon	Oliver
Before	9 u	5 u	10 u	6 u
Change		- 5 u		+ 5 u
After	9 u	0 u	10 u	11 u

Amount that Oliver had if Xavier gave him all his money
= 6 u + 5 u
= 11 u

Amount that Oliver had more than Dylan
= 11 u - 9 u
= 2 u
= 2 x 3
= $6

Answer(s): $6