Justin, Tommy, Albert and Cody shared $140. Cody received
16 of the total amount of money received by Justin, Tommy and Albert. Justin received
35 of the total amount for Tommy and Albert. Tommy received
12 as much money as Albert. If Albert gave all his money to Cody, how much did Cody have more than Tommy in the end?
Justin |
Tommy |
Albert |
Cody |
Total |
6x4 |
1x4 |
7x4 |
3x3 |
5x3 |
|
|
|
1x5 |
2x5 |
|
|
9 u |
5 u |
10 u |
4 u |
28 u |
The total amount that Tommy and Albert have is repeated. Make the total amount of Tommy and Albert the same. LCM of 3 and 5 is 15.
The total amount that Justin, Tommy and Albert have is repeated. Make the total amount of Justin, Tommy and Albert the same. LCM of 24 and 6 is 24.
Total amount that Justin, Tommy, Albert and Cody shared = 28 u
28 u = 140
1 u = 140 ÷ 28 = 5
|
Justin |
Tommy |
Albert |
Cody |
Before |
9 u |
5 u |
10 u |
4 u |
Change |
|
|
- 10 u |
+ 10 u |
After |
9 u |
5 u |
0 u |
14 u |
Amount that Cody had if Albert gave him all his money
= 4 u + 10 u
= 14 u
Amount that Cody had more than Tommy
= 14 u - 5 u
= 9 u
= 9 x 5
= $45
Answer(s): $45