Wesley, Ryan, Howard and Sam shared $375. Sam received
14 of the total amount of money received by Wesley, Ryan and Howard. Wesley received
23 of the total amount for Ryan and Howard. Ryan received
13 as much money as Howard. If Howard gave all his money to Sam, how much did Sam have more than Ryan in the end?
Wesley |
Ryan |
Howard |
Sam |
Total |
4x5 |
1x5 |
5x5 |
2x4 |
3x4 |
|
|
|
1x3 |
3x3 |
|
|
8 u |
3 u |
9 u |
5 u |
25 u |
The total amount that Ryan and Howard have is repeated. Make the total amount of Ryan and Howard the same. LCM of 4 and 3 is 12.
The total amount that Wesley, Ryan and Howard have is repeated. Make the total amount of Wesley, Ryan and Howard the same. LCM of 20 and 4 is 20.
Total amount that Wesley, Ryan, Howard and Sam shared = 25 u
25 u = 375
1 u = 375 ÷ 25 = 15
|
Wesley |
Ryan |
Howard |
Sam |
Before |
8 u |
3 u |
9 u |
5 u |
Change |
|
|
- 9 u |
+ 9 u |
After |
8 u |
3 u |
0 u |
14 u |
Amount that Sam had if Howard gave him all his money
= 5 u + 9 u
= 14 u
Amount that Sam had more than Ryan
= 14 u - 3 u
= 11 u
= 11 x 15
= $165
Answer(s): $165