Sean, Julian, Nick and Jeremy shared $75. Jeremy received
23 of the total amount of money received by Sean, Julian and Nick. Sean received
14 of the total amount for Julian and Nick. Julian received
12 as much money as Nick. If Nick gave all his money to Jeremy, how much did Jeremy have more than Julian in the end?
Sean |
Julian |
Nick |
Jeremy |
Total |
3x5 |
2x5 |
5x5 |
1x3 |
4x3 |
|
|
|
1x4 |
2x4 |
|
|
3 u |
4 u |
8 u |
10 u |
25 u |
The total amount that Julian and Nick have is repeated. Make the total amount of Julian and Nick the same. LCM of 3 and 4 is 12.
The total amount that Sean, Julian and Nick have is repeated. Make the total amount of Sean, Julian and Nick the same. LCM of 15 and 3 is 15.
Total amount that Sean, Julian, Nick and Jeremy shared = 25 u
25 u = 75
1 u = 75 ÷ 25 = 3
|
Sean |
Julian |
Nick |
Jeremy |
Before |
3 u |
4 u |
8 u |
10 u |
Change |
|
|
- 8 u |
+ 8 u |
After |
3 u |
4 u |
0 u |
18 u |
Amount that Jeremy had if Nick gave him all his money
= 10 u + 8 u
= 18 u
Amount that Jeremy had more than Julian
= 18 u - 4 u
= 14 u
= 14 x 3
= $42
Answer(s): $42