David, Elijah, Bryan and Sean shared $420. Sean received
25 of the total amount of money received by David, Elijah and Bryan. David received
13 of the total amount for Elijah and Bryan. Elijah received
23 as much money as Bryan. If Elijah gave all his money to Sean, how much did Sean have more than David in the end?
David |
Elijah |
Bryan |
Sean |
Total |
5x4 |
2x4 |
7x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
8 u |
28 u |
The total amount that Elijah and Bryan have is repeated. Make the total amount of Elijah and Bryan the same. LCM of 5 and 3 is 15.
The total amount that David, Elijah and Bryan have is repeated. Make the total amount of David, Elijah and Bryan the same. LCM of 20 and 5 is 20.
Total amount that David, Elijah, Bryan and Sean shared = 28 u
28 u = 420
1 u = 420 ÷ 28 = 15
|
David |
Elijah |
Bryan |
Sean |
Before |
5 u |
6 u |
9 u |
8 u |
Change |
|
- 6 u |
|
+ 6 u |
After |
5 u |
0 u |
9 u |
14 u |
Amount that Sean had if Elijah gave him all his money
= 8 u + 6 u
= 14 u
Amount that Sean had more than David
= 14 u - 5 u
= 9 u
= 9 x 15
= $135
Answer(s): $135