Billy, Gabriel, Xavier and Jack shared $1056. Jack received
56 of the total amount of money received by Billy, Gabriel and Xavier. Billy received
45 of the total amount for Gabriel and Xavier. Gabriel received
13 as much money as Xavier. If Xavier gave all his money to Jack, how much did Jack have more than Gabriel in the end?
Billy |
Gabriel |
Xavier |
Jack |
Total |
6x6 |
5x6 |
11x6 |
4x4 |
5x4 |
|
|
|
1x5 |
3x5 |
|
|
16 u |
5 u |
15 u |
30 u |
66 u |
The total amount that Gabriel and Xavier have is repeated. Make the total amount of Gabriel and Xavier the same. LCM of 4 and 5 is 20.
The total amount that Billy, Gabriel and Xavier have is repeated. Make the total amount of Billy, Gabriel and Xavier the same. LCM of 36 and 6 is 36.
Total amount that Billy, Gabriel, Xavier and Jack shared = 66 u
66 u = 1056
1 u = 1056 ÷ 66 = 16
|
Billy |
Gabriel |
Xavier |
Jack |
Before |
16 u |
5 u |
15 u |
30 u |
Change |
|
|
- 15 u |
+ 15 u |
After |
16 u |
5 u |
0 u |
45 u |
Amount that Jack had if Xavier gave him all his money
= 30 u + 15 u
= 45 u
Amount that Jack had more than Gabriel
= 45 u - 5 u
= 40 u
= 40 x 16
= $640
Answer(s): $640