Owen, Howard, Dylan and Lee shared $168. Lee received ¹₅ of the total amount of money received by Owen, Howard and Dylan. Owen received ¹₃ of the total amount for Howard and Dylan. Howard received ²₃ as much money as Dylan. If Howard gave all his money to Lee, how much did Lee have more than Owen in the end?

Owen	Howard	Dylan	Lee	Total
5x4			1x4	6x4
1x5	3x5
	2x3	3x3
5 u	6 u	9 u	4 u	24 u

The total amount that Howard and Dylan have is repeated.  Make the total amount of Howard and Dylan the same.  LCM of 5 and 3 is 15.

The total amount that Owen, Howard and Dylan have is repeated.  Make the total amount of Owen, Howard and Dylan the same. LCM of 20 and 5 is 20.

Total amount that Owen, Howard, Dylan and Lee shared = 24 u

24 u = 168

1 u = 168 ÷ 24 = 7

	Owen	Howard	Dylan	Lee
Before	5 u	6 u	9 u	4 u
Change		- 6 u		+ 6 u
After	5 u	0 u	9 u	10 u

Amount that Lee had if Howard gave him all his money
= 4 u + 6 u
= 10 u

Amount that Lee had more than Owen
= 10 u - 5 u
= 5 u
= 5 x 7
= $35

Answer(s): $35