Lee, Peter, Liam and Tommy shared $108. Tommy received ⁴₅ of the total amount of money received by Lee, Peter and Liam. Lee received ¹₃ of the total amount for Peter and Liam. Peter received ²₃ as much money as Liam. If Liam gave all his money to Tommy, how much did Tommy have more than Peter in the end?

Lee	Peter	Liam	Tommy	Total
5x4			4x4	9x4
1x5	3x5
	2x3	3x3
5 u	6 u	9 u	16 u	36 u

The total amount that Peter and Liam have is repeated.  Make the total amount of Peter and Liam the same.  LCM of 5 and 3 is 15.

The total amount that Lee, Peter and Liam have is repeated.  Make the total amount of Lee, Peter and Liam the same. LCM of 20 and 5 is 20.

Total amount that Lee, Peter, Liam and Tommy shared = 36 u

36 u = 108

1 u = 108 ÷ 36 = 3

	Lee	Peter	Liam	Tommy
Before	5 u	6 u	9 u	16 u
Change			- 9 u	+ 9 u
After	5 u	6 u	0 u	25 u

Amount that Tommy had if Liam gave him all his money
= 16 u + 9 u
= 25 u

Amount that Tommy had more than Peter
= 25 u - 6 u
= 19 u
= 19 x 3
= $57

Answer(s): $57