Sean, Cody, Albert and Rael shared $570. Rael received ¹₄ of the total amount of money received by Sean, Cody and Albert. Sean received ³₅ of the total amount for Cody and Albert. Cody received ¹₂ as much money as Albert. If Cody gave all his money to Rael, how much did Rael have more than Sean in the end?

Sean	Cody	Albert	Rael	Total
4x6			1x6	5x6
3x3	5x3
	1x5	2x5
9 u	5 u	10 u	6 u	30 u

The total amount that Cody and Albert have is repeated.  Make the total amount of Cody and Albert the same.  LCM of 3 and 5 is 15.

The total amount that Sean, Cody and Albert have is repeated.  Make the total amount of Sean, Cody and Albert the same. LCM of 24 and 4 is 24.

Total amount that Sean, Cody, Albert and Rael shared = 30 u

30 u = 570

1 u = 570 ÷ 30 = 19

	Sean	Cody	Albert	Rael
Before	9 u	5 u	10 u	6 u
Change		- 5 u		+ 5 u
After	9 u	0 u	10 u	11 u

Amount that Rael had if Cody gave him all his money
= 6 u + 5 u
= 11 u

Amount that Rael had more than Sean
= 11 u - 9 u
= 2 u
= 2 x 19
= $38

Answer(s): $38