Eric, Lee, Archie and Luke shared $324. Luke received
45 of the total amount of money received by Eric, Lee and Archie. Eric received
13 of the total amount for Lee and Archie. Lee received
23 as much money as Archie. If Lee gave all his money to Luke, how much did Luke have more than Eric in the end?
Eric |
Lee |
Archie |
Luke |
Total |
5x4 |
4x4 |
9x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
16 u |
36 u |
The total amount that Lee and Archie have is repeated. Make the total amount of Lee and Archie the same. LCM of 5 and 3 is 15.
The total amount that Eric, Lee and Archie have is repeated. Make the total amount of Eric, Lee and Archie the same. LCM of 20 and 5 is 20.
Total amount that Eric, Lee, Archie and Luke shared = 36 u
36 u = 324
1 u = 324 ÷ 36 = 9
|
Eric |
Lee |
Archie |
Luke |
Before |
5 u |
6 u |
9 u |
16 u |
Change |
|
- 6 u |
|
+ 6 u |
After |
5 u |
0 u |
9 u |
22 u |
Amount that Luke had if Lee gave him all his money
= 16 u + 6 u
= 22 u
Amount that Luke had more than Eric
= 22 u - 5 u
= 17 u
= 17 x 9
= $153
Answer(s): $153