Owen, John, Xavier and Dylan shared $640. Dylan received
35 of the total amount of money received by Owen, John and Xavier. Owen received
13 of the total amount for John and Xavier. John received
23 as much money as Xavier. If Xavier gave all his money to Dylan, how much did Dylan have more than John in the end?
Owen |
John |
Xavier |
Dylan |
Total |
5x4 |
3x4 |
8x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
12 u |
32 u |
The total amount that John and Xavier have is repeated. Make the total amount of John and Xavier the same. LCM of 5 and 3 is 15.
The total amount that Owen, John and Xavier have is repeated. Make the total amount of Owen, John and Xavier the same. LCM of 20 and 5 is 20.
Total amount that Owen, John, Xavier and Dylan shared = 32 u
32 u = 640
1 u = 640 ÷ 32 = 20
|
Owen |
John |
Xavier |
Dylan |
Before |
5 u |
6 u |
9 u |
12 u |
Change |
|
|
- 9 u |
+ 9 u |
After |
5 u |
6 u |
0 u |
21 u |
Amount that Dylan had if Xavier gave him all his money
= 12 u + 9 u
= 21 u
Amount that Dylan had more than John
= 21 u - 6 u
= 15 u
= 15 x 20
= $300
Answer(s): $300