Wesley, Pierre, Fabian and Eric shared $500. Eric received
23 of the total amount of money received by Wesley, Pierre and Fabian. Wesley received
14 of the total amount for Pierre and Fabian. Pierre received
12 as much money as Fabian. If Pierre gave all his money to Eric, how much did Eric have more than Wesley in the end?
Wesley |
Pierre |
Fabian |
Eric |
Total |
3x5 |
2x5 |
5x5 |
1x3 |
4x3 |
|
|
|
1x4 |
2x4 |
|
|
3 u |
4 u |
8 u |
10 u |
25 u |
The total amount that Pierre and Fabian have is repeated. Make the total amount of Pierre and Fabian the same. LCM of 3 and 4 is 12.
The total amount that Wesley, Pierre and Fabian have is repeated. Make the total amount of Wesley, Pierre and Fabian the same. LCM of 15 and 3 is 15.
Total amount that Wesley, Pierre, Fabian and Eric shared = 25 u
25 u = 500
1 u = 500 ÷ 25 = 20
|
Wesley |
Pierre |
Fabian |
Eric |
Before |
3 u |
4 u |
8 u |
10 u |
Change |
|
- 4 u |
|
+ 4 u |
After |
3 u |
0 u |
8 u |
14 u |
Amount that Eric had if Pierre gave him all his money
= 10 u + 4 u
= 14 u
Amount that Eric had more than Wesley
= 14 u - 3 u
= 11 u
= 11 x 20
= $220
Answer(s): $220