Jack, Rael, Jeremy and Lee shared $468. Lee received
45 of the total amount of money received by Jack, Rael and Jeremy. Jack received
13 of the total amount for Rael and Jeremy. Rael received
23 as much money as Jeremy. If Rael gave all his money to Lee, how much did Lee have more than Jack in the end?
Jack |
Rael |
Jeremy |
Lee |
Total |
5x4 |
4x4 |
9x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
16 u |
36 u |
The total amount that Rael and Jeremy have is repeated. Make the total amount of Rael and Jeremy the same. LCM of 5 and 3 is 15.
The total amount that Jack, Rael and Jeremy have is repeated. Make the total amount of Jack, Rael and Jeremy the same. LCM of 20 and 5 is 20.
Total amount that Jack, Rael, Jeremy and Lee shared = 36 u
36 u = 468
1 u = 468 ÷ 36 = 13
|
Jack |
Rael |
Jeremy |
Lee |
Before |
5 u |
6 u |
9 u |
16 u |
Change |
|
- 6 u |
|
+ 6 u |
After |
5 u |
0 u |
9 u |
22 u |
Amount that Lee had if Rael gave him all his money
= 16 u + 6 u
= 22 u
Amount that Lee had more than Jack
= 22 u - 5 u
= 17 u
= 17 x 13
= $221
Answer(s): $221