Riordan, Oliver, Jenson and Pierre shared $140. Pierre received
34 of the total amount of money received by Riordan, Oliver and Jenson. Riordan received
23 of the total amount for Oliver and Jenson. Oliver received
13 as much money as Jenson. If Oliver gave all his money to Pierre, how much did Pierre have more than Riordan in the end?
Riordan |
Oliver |
Jenson |
Pierre |
Total |
4x5 |
3x5 |
7x5 |
2x4 |
3x4 |
|
|
|
1x3 |
3x3 |
|
|
8 u |
3 u |
9 u |
15 u |
35 u |
The total amount that Oliver and Jenson have is repeated. Make the total amount of Oliver and Jenson the same. LCM of 4 and 3 is 12.
The total amount that Riordan, Oliver and Jenson have is repeated. Make the total amount of Riordan, Oliver and Jenson the same. LCM of 20 and 4 is 20.
Total amount that Riordan, Oliver, Jenson and Pierre shared = 35 u
35 u = 140
1 u = 140 ÷ 35 = 4
|
Riordan |
Oliver |
Jenson |
Pierre |
Before |
8 u |
3 u |
9 u |
15 u |
Change |
|
- 3 u |
|
+ 3 u |
After |
8 u |
0 u |
9 u |
18 u |
Amount that Pierre had if Oliver gave him all his money
= 15 u + 3 u
= 18 u
Amount that Pierre had more than Riordan
= 18 u - 8 u
= 10 u
= 10 x 4
= $40
Answer(s): $40