Michael, Vaidev, Dylan and Tommy shared $84. Tommy received
16 of the total amount of money received by Michael, Vaidev and Dylan. Michael received
45 of the total amount for Vaidev and Dylan. Vaidev received
13 as much money as Dylan. If Vaidev gave all his money to Tommy, how much did Tommy have more than Michael in the end?
Michael |
Vaidev |
Dylan |
Tommy |
Total |
6x6 |
1x6 |
7x6 |
4x4 |
5x4 |
|
|
|
1x5 |
3x5 |
|
|
16 u |
5 u |
15 u |
6 u |
42 u |
The total amount that Vaidev and Dylan have is repeated. Make the total amount of Vaidev and Dylan the same. LCM of 4 and 5 is 20.
The total amount that Michael, Vaidev and Dylan have is repeated. Make the total amount of Michael, Vaidev and Dylan the same. LCM of 36 and 6 is 36.
Total amount that Michael, Vaidev, Dylan and Tommy shared = 42 u
42 u = 84
1 u = 84 ÷ 42 = 2
|
Michael |
Vaidev |
Dylan |
Tommy |
Before |
16 u |
5 u |
15 u |
6 u |
Change |
|
- 5 u |
|
+ 5 u |
After |
16 u |
0 u |
15 u |
11 u |
Amount that Tommy had if Vaidev gave him all his money
= 6 u + 5 u
= 11 u
Amount that Tommy had more than Michael
= 11 u - 16 u
= -5 u
= -5 x 2
= $-10
Answer(s): $-10