Bobby, Zane, Luke and Seth shared $224. Seth received
25 of the total amount of money received by Bobby, Zane and Luke. Bobby received
13 of the total amount for Zane and Luke. Zane received
23 as much money as Luke. If Luke gave all his money to Seth, how much did Seth have more than Zane in the end?
Bobby |
Zane |
Luke |
Seth |
Total |
5x4 |
2x4 |
7x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
8 u |
28 u |
The total amount that Zane and Luke have is repeated. Make the total amount of Zane and Luke the same. LCM of 5 and 3 is 15.
The total amount that Bobby, Zane and Luke have is repeated. Make the total amount of Bobby, Zane and Luke the same. LCM of 20 and 5 is 20.
Total amount that Bobby, Zane, Luke and Seth shared = 28 u
28 u = 224
1 u = 224 ÷ 28 = 8
|
Bobby |
Zane |
Luke |
Seth |
Before |
5 u |
6 u |
9 u |
8 u |
Change |
|
|
- 9 u |
+ 9 u |
After |
5 u |
6 u |
0 u |
17 u |
Amount that Seth had if Luke gave him all his money
= 8 u + 9 u
= 17 u
Amount that Seth had more than Zane
= 17 u - 6 u
= 11 u
= 11 x 8
= $88
Answer(s): $88