Ian, Paul, Pierre and Gabriel shared $360. Gabriel received ⁴₅ of the total amount of money received by Ian, Paul and Pierre. Ian received ¹₃ of the total amount for Paul and Pierre. Paul received ²₃ as much money as Pierre. If Paul gave all his money to Gabriel, how much did Gabriel have more than Ian in the end?

Ian	Paul	Pierre	Gabriel	Total
5x4			4x4	9x4
1x5	3x5
	2x3	3x3
5 u	6 u	9 u	16 u	36 u

The total amount that Paul and Pierre have is repeated.  Make the total amount of Paul and Pierre the same.  LCM of 5 and 3 is 15.

The total amount that Ian, Paul and Pierre have is repeated.  Make the total amount of Ian, Paul and Pierre the same. LCM of 20 and 5 is 20.

Total amount that Ian, Paul, Pierre and Gabriel shared = 36 u

36 u = 360

1 u = 360 ÷ 36 = 10

	Ian	Paul	Pierre	Gabriel
Before	5 u	6 u	9 u	16 u
Change		- 6 u		+ 6 u
After	5 u	0 u	9 u	22 u

Amount that Gabriel had if Paul gave him all his money
= 16 u + 6 u
= 22 u

Amount that Gabriel had more than Ian
= 22 u - 5 u
= 17 u
= 17 x 10
= $170

Answer(s): $170