David, Ken, Lee and Vincent shared $378. Vincent received
16 of the total amount of money received by David, Ken and Lee. David received
45 of the total amount for Ken and Lee. Ken received
13 as much money as Lee. If Ken gave all his money to Vincent, how much did Vincent have more than David in the end?
David |
Ken |
Lee |
Vincent |
Total |
6x6 |
1x6 |
7x6 |
4x4 |
5x4 |
|
|
|
1x5 |
3x5 |
|
|
16 u |
5 u |
15 u |
6 u |
42 u |
The total amount that Ken and Lee have is repeated. Make the total amount of Ken and Lee the same. LCM of 4 and 5 is 20.
The total amount that David, Ken and Lee have is repeated. Make the total amount of David, Ken and Lee the same. LCM of 36 and 6 is 36.
Total amount that David, Ken, Lee and Vincent shared = 42 u
42 u = 378
1 u = 378 ÷ 42 = 9
|
David |
Ken |
Lee |
Vincent |
Before |
16 u |
5 u |
15 u |
6 u |
Change |
|
- 5 u |
|
+ 5 u |
After |
16 u |
0 u |
15 u |
11 u |
Amount that Vincent had if Ken gave him all his money
= 6 u + 5 u
= 11 u
Amount that Vincent had more than David
= 11 u - 16 u
= -5 u
= -5 x 9
= $-45
Answer(s): $-45