Perry, Albert, Justin and Cole shared $84. Cole received
25 of the total amount of money received by Perry, Albert and Justin. Perry received
13 of the total amount for Albert and Justin. Albert received
23 as much money as Justin. If Justin gave all his money to Cole, how much did Cole have more than Albert in the end?
Perry |
Albert |
Justin |
Cole |
Total |
5x4 |
2x4 |
7x4 |
1x5 |
3x5 |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
8 u |
28 u |
The total amount that Albert and Justin have is repeated. Make the total amount of Albert and Justin the same. LCM of 5 and 3 is 15.
The total amount that Perry, Albert and Justin have is repeated. Make the total amount of Perry, Albert and Justin the same. LCM of 20 and 5 is 20.
Total amount that Perry, Albert, Justin and Cole shared = 28 u
28 u = 84
1 u = 84 ÷ 28 = 3
|
Perry |
Albert |
Justin |
Cole |
Before |
5 u |
6 u |
9 u |
8 u |
Change |
|
|
- 9 u |
+ 9 u |
After |
5 u |
6 u |
0 u |
17 u |
Amount that Cole had if Justin gave him all his money
= 8 u + 9 u
= 17 u
Amount that Cole had more than Albert
= 17 u - 6 u
= 11 u
= 11 x 3
= $33
Answer(s): $33