Cole, Carl, Vincent and Xavier shared $792. Xavier received
56 of the total amount of money received by Cole, Carl and Vincent. Cole received
45 of the total amount for Carl and Vincent. Carl received
13 as much money as Vincent. If Carl gave all his money to Xavier, how much did Xavier have more than Cole in the end?
Cole |
Carl |
Vincent |
Xavier |
Total |
6x6 |
5x6 |
11x6 |
4x4 |
5x4 |
|
|
|
1x5 |
3x5 |
|
|
16 u |
5 u |
15 u |
30 u |
66 u |
The total amount that Carl and Vincent have is repeated. Make the total amount of Carl and Vincent the same. LCM of 4 and 5 is 20.
The total amount that Cole, Carl and Vincent have is repeated. Make the total amount of Cole, Carl and Vincent the same. LCM of 36 and 6 is 36.
Total amount that Cole, Carl, Vincent and Xavier shared = 66 u
66 u = 792
1 u = 792 ÷ 66 = 12
|
Cole |
Carl |
Vincent |
Xavier |
Before |
16 u |
5 u |
15 u |
30 u |
Change |
|
- 5 u |
|
+ 5 u |
After |
16 u |
0 u |
15 u |
35 u |
Amount that Xavier had if Carl gave him all his money
= 30 u + 5 u
= 35 u
Amount that Xavier had more than Cole
= 35 u - 16 u
= 19 u
= 19 x 12
= $228
Answer(s): $228