Howard, Asher, Caden and Dylan shared $663. Dylan received ¹₁₂ of the total amount of money received by Howard, Asher and Caden. Howard received ⁴₅ of the total amount for Asher and Caden. Asher received ¹₃ as much money as Caden. If Asher gave all his money to Dylan, how much did Dylan have more than Howard in the end?

Howard	Asher	Caden	Dylan	Total
12x3			1x3	13x3
4x4	5x4
	1x5	3x5
16 u	5 u	15 u	3 u	39 u

The total amount that Asher and Caden have is repeated.  Make the total amount of Asher and Caden the same.  LCM of 4 and 5 is 20.

The total amount that Howard, Asher and Caden have is repeated.  Make the total amount of Howard, Asher and Caden the same. LCM of 36 and 12 is 36.

Total amount that Howard, Asher, Caden and Dylan shared = 39 u

39 u = 663

1 u = 663 ÷ 39 = 17

	Howard	Asher	Caden	Dylan
Before	16 u	5 u	15 u	3 u
Change		- 5 u		+ 5 u
After	16 u	0 u	15 u	8 u

Amount that Dylan had if Asher gave him all his money
= 3 u + 5 u
= 8 u

Amount that Dylan had more than Howard
= 8 u - 16 u
= -8 u
= -8 x 17
= $-136

Answer(s): $-136