Tim, Ryan, Gabriel and Xavier shared $308. Xavier received ⁵₆ of the total amount of money received by Tim, Ryan and Gabriel. Tim received ³₅ of the total amount for Ryan and Gabriel. Ryan received ¹₂ as much money as Gabriel. If Ryan gave all his money to Xavier, how much did Xavier have more than Tim in the end?

Tim	Ryan	Gabriel	Xavier	Total
6x4			5x4	11x4
3x3	5x3
	1x5	2x5
9 u	5 u	10 u	20 u	44 u

The total amount that Ryan and Gabriel have is repeated.  Make the total amount of Ryan and Gabriel the same.  LCM of 3 and 5 is 15.

The total amount that Tim, Ryan and Gabriel have is repeated.  Make the total amount of Tim, Ryan and Gabriel the same. LCM of 24 and 6 is 24.

Total amount that Tim, Ryan, Gabriel and Xavier shared = 44 u

44 u = 308

1 u = 308 ÷ 44 = 7

	Tim	Ryan	Gabriel	Xavier
Before	9 u	5 u	10 u	20 u
Change		- 5 u		+ 5 u
After	9 u	0 u	10 u	25 u

Amount that Xavier had if Ryan gave him all his money
= 20 u + 5 u
= 25 u

Amount that Xavier had more than Tim
= 25 u - 9 u
= 16 u
= 16 x 7
= $112

Answer(s): $112