Tim, Perry, Riordan and Ahmad shared $392. Ahmad received
16 of the total amount of money received by Tim, Perry and Riordan. Tim received
35 of the total amount for Perry and Riordan. Perry received
12 as much money as Riordan. If Riordan gave all his money to Ahmad, how much did Ahmad have more than Perry in the end?
Tim |
Perry |
Riordan |
Ahmad |
Total |
6x4 |
1x4 |
7x4 |
3x3 |
5x3 |
|
|
|
1x5 |
2x5 |
|
|
9 u |
5 u |
10 u |
4 u |
28 u |
The total amount that Perry and Riordan have is repeated. Make the total amount of Perry and Riordan the same. LCM of 3 and 5 is 15.
The total amount that Tim, Perry and Riordan have is repeated. Make the total amount of Tim, Perry and Riordan the same. LCM of 24 and 6 is 24.
Total amount that Tim, Perry, Riordan and Ahmad shared = 28 u
28 u = 392
1 u = 392 ÷ 28 = 14
|
Tim |
Perry |
Riordan |
Ahmad |
Before |
9 u |
5 u |
10 u |
4 u |
Change |
|
|
- 10 u |
+ 10 u |
After |
9 u |
5 u |
0 u |
14 u |
Amount that Ahmad had if Riordan gave him all his money
= 4 u + 10 u
= 14 u
Amount that Ahmad had more than Perry
= 14 u - 5 u
= 9 u
= 9 x 14
= $126
Answer(s): $126